Python program to find sum of the series 1/1! + 2/2! + 3/3! + ……1/n!; Through this tutorial, i am going to show you how to find sum of the series 1/1! + 2/2! + 3/3! + ……1/n! in python.

## Python Program to Find The Sum of Series 1/1! 2/2! 3/3! …1/n!

See the following python program to find sum of the series : 1 + 1/2 + 1/3 + ….. + 1/N using for loop and function; as shown below:

- Python Program to Find the Sum of the Series: 1 + 1/2 + 1/3 + …..+ 1/N using For Loop
- Python Program to Find Sum of Series 1/1! 2/2! 3/3! …1/n! Using Function

### Python Program to Find the Sum of the Series: 1 + 1/2 + 1/3 + …..+ 1/N using For Loop

- Get input number of terms to find the sum of the series from user.
- Initialize the sum variable to 0.
- Use a for loop ranging from 1 to the number and find the sum of the series.
- Print the sum of the series after rounding it off to two decimal places.

#Python Program to Find Sum of Series 1/1! 2/2! 3/3! …1/n! using for loop n=int(input("Enter the number of terms: ")) sum1=0 for i in range(1,n+1): sum1=sum1+(1/i) print("The sum of series is",round(sum1,2))

**Output**

Enter the number of terms: 5 The sum of series is 2.28

### Python Program to Find Sum of Series 1/1! 2/2! 3/3! …1/n! Using Function

- Get the input number of the term of series from the user.
- Next, Define a function and write logic to computes the sum of series for a given number.
- Call function with number.
- Print the sum of the series return by function.

#Python Program to Find Sum of Series 1/1! 2/2! 3/3! …1/n! using function #define a function def sumOfSeries(num): # Computing MAX res = 0 fact = 1 for i in range(1, num+1): fact *= i res = res + (i/ fact) return res n=int(input("Enter the number of terms: ")) print("Sum: ", sumOfSeries(n))

Enter the number of terms: 5 Sum: 2.708333333333333

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